xep_0363: change filename to Path

This shouldn't break anything as I'm not using Path specific APIs

Signed-off-by: Maxime “pep” Buquet <pep@bouah.net>
This commit is contained in:
Maxime “pep” Buquet 2022-03-17 20:59:05 +01:00
parent 54b724c28b
commit 3c08f471cf

View file

@ -14,6 +14,8 @@ from typing import (
IO,
)
from pathlib import Path
from slixmpp import JID, __version__
from slixmpp.stanza import Iq
from slixmpp.plugins import BasePlugin
@ -113,7 +115,7 @@ class XEP_0363(BasePlugin):
if feature == Request.namespace:
return info
def request_slot(self, jid: JID, filename: str, size: int,
def request_slot(self, jid: JID, filename: Path, size: int,
content_type: Optional[str] = None, *,
ifrom: Optional[JID] = None, **iqkwargs) -> Future:
"""Request an HTTP upload slot from a service.
@ -125,12 +127,12 @@ class XEP_0363(BasePlugin):
"""
iq = self.xmpp.make_iq_get(ito=jid, ifrom=ifrom)
request = iq['http_upload_request']
request['filename'] = filename
request['filename'] = str(filename)
request['size'] = str(size)
request['content-type'] = content_type or self.default_content_type
return iq.send(**iqkwargs)
async def upload_file(self, filename: str, size: Optional[int] = None,
async def upload_file(self, filename: Path, size: Optional[int] = None,
content_type: Optional[str] = None, *,
input_file: Optional[IO[bytes]]=None,
domain: Optional[JID] = None,