86 lines
2.8 KiB
Python
86 lines
2.8 KiB
Python
# -*- coding: utf-8 -*-
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"""
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sleekxmpp.xmlstream.matcher.xpath
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Part of SleekXMPP: The Sleek XMPP Library
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:copyright: (c) 2011 Nathanael C. Fritz
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:license: MIT, see LICENSE for more details
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"""
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from sleekxmpp.xmlstream.stanzabase import ET
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from sleekxmpp.xmlstream.matcher.base import MatcherBase
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# Flag indicating if the builtin XPath matcher should be used, which
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# uses namespaces, or a custom matcher that ignores namespaces.
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# Changing this will affect ALL XPath matchers.
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IGNORE_NS = False
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class MatchXPath(MatcherBase):
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"""
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The XPath matcher selects stanzas whose XML contents matches a given
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XPath expression.
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.. warning::
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Using this matcher may not produce expected behavior when using
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attribute selectors. For Python 2.6 and 3.1, the ElementTree
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:meth:`~xml.etree.ElementTree.Element.find()` method does
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not support the use of attribute selectors. If you need to
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support Python 2.6 or 3.1, it might be more useful to use a
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:class:`~sleekxmpp.xmlstream.matcher.stanzapath.StanzaPath` matcher.
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If the value of :data:`IGNORE_NS` is set to ``True``, then XPath
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expressions will be matched without using namespaces.
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"""
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def match(self, xml):
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"""
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Compare a stanza's XML contents to an XPath expression.
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If the value of :data:`IGNORE_NS` is set to ``True``, then XPath
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expressions will be matched without using namespaces.
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.. warning::
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In Python 2.6 and 3.1 the ElementTree
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:meth:`~xml.etree.ElementTree.Element.find()` method does not
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support attribute selectors in the XPath expression.
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:param xml: The :class:`~sleekxmpp.xmlstream.stanzabase.ElementBase`
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stanza to compare against.
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"""
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if hasattr(xml, 'xml'):
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xml = xml.xml
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x = ET.Element('x')
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x.append(xml)
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if not IGNORE_NS:
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# Use builtin, namespace respecting, XPath matcher.
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if x.find(self._criteria) is not None:
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return True
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return False
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else:
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# Remove namespaces from the XPath expression.
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criteria = []
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for ns_block in self._criteria.split('{'):
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criteria.extend(ns_block.split('}')[-1].split('/'))
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# Walk the XPath expression.
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xml = x
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for tag in criteria:
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if not tag:
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# Skip empty tag name artifacts from the cleanup phase.
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continue
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children = [c.tag.split('}')[-1] for c in xml.getchildren()]
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try:
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index = children.index(tag)
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except ValueError:
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return False
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xml = xml.getchildren()[index]
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return True
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